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[원서] Charles K.Alexander,Matthew N. O.Sadiku - Fundamentals of Electri…

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[원서] Charles K.Alexander,Matthew N. O.Sadiku - Fundamentals of Electric Circuits - Instructor Solutions M

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솔루션,전기전자,솔루션
[원서] Charles K.Alexander,Matthew N. O.Sadiku - Fundamentals of Electric Circuits - Instructor Solutions M





Download : Charles K Alexander Matthew N O Sadiku Fundamentals of Electric Circuits Instructor Solutions M.pdf( 34 )


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[원서] Charles K.Alexander,Matthew N. O.Sadiku - Fundamentals of Electric Circuits - Instructor Solutions M , [원서] Charles K.Alexander,Matthew N. O.Sadiku - Fundamentals of Electric Circuits - Instructor Solutions M전기전자솔루션 , 솔루션


FiFt h Edition

Fundamentals of

Electric Circuits
INSTRUCTOR SOLUTIONS MANUAL

Charles K. Alexander | Matthew n. o. Sadiku

Chapter 1, Solution 1 (a) q = 6.482x1017 x [-1.602x10-19 C] = 103.84 mC (b) q = 1. 24x1018 x [-1.602x10-19 C] = 198.65 mC (c) q = 2.46x1019 x [-1.602x10-19 C] = 3.941 C (d) q = 1.628x1020 x [-1.602x10-19 C] = 26.08 C

Chapter 1, Solution 2

(a) (b) (c) (d) (e)

i = dq/dt = 3 mA i = dq/dt = (16t + 4) A i = dq/dt = (-3e-t + 10e-2t) nA i=dq/dt = 1200 cos 120 t

FiFt h Edition

Fundamentals of

Electric Circuits
INSTRUCTOR SOLUTIONS MANUAL

Charles K. Alexander | Matthew n. o. Sadiku

Chapter 1, Solution 1 (a) q = 6.482x1xxx x [-1.602x10-19 C] = 103.84 mC (b) q = 1. 24x1xxx x [-1.602x10-19 C] = 198.65 mC (c) q = 2.46x1xxx x [-1.602x10-19 C] = 3.941 C (d) q = 1.628x1020 x [-1.602x10-19 C] = 26.08 C…(skip)
다.
REPORT 73(sv75)


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