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[solution(솔루션)] 일반화학 7판 solution(솔루션)(사이플러스)

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작성일 20-10-16 16:54

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Download : [솔루션] 일반화학 7판 솔루션(사이.zip




총 1장부터 22장까지의 솔루션이 있습니다. 기초과학인 일반화학 수업을 듣기 위한 솔루션입니다. For the above number expressed in scientific notation, n  6. The decimal place must be moved 6 places to the right to convert to nonscientific notation.
Since 0.000000621 is a number less than one, n is a negative integer. In this case, n  7.
Strategy: Lets express scientific notation as N  10n. When dividing numbers using scientific notation, divide the N parts of the numbers in the usual way. To come up with the correct exponent, n, we subtract the exponents.

(c) Subtraction using scientific notation.
653  6.53  102
기초과학인 일반화학 수업을 듣기 위한 solution(솔루션)입니다.





다.
1.25 (a) 145.75  (2.3  101)  145.75  0.23  1.4598  102
Divide the N parts of the numbers in the usual way.
Strategy: Lets express scientific notation as N  10n. When adding numbers using scientific notation, we must write each quantity with the same exponent, n. We can then add the N parts of the numbers, keeping the exponent, n, the same.

Since 802.6 is a number greater than one, n is a positive integer. In this case, n  2.

The usual practice is to express N as a number between 1 and 10. Since we must decrease N by a factor of 10 to express N between 1 and 10 (1.8), we must increase 10n by a factor of 10. The exponent, n, is increased by 1 from 3 to 2.
9.5  103


(d) (1.0  104)  (9.9  106)  9.9  1010
Let’s write 850,000 in such a way that n  5. This means to move the decimal point five places to the left.
850,000  8.5  105

3.256  105  0.00003256






Solution: Write each quantity with the same exponent, n.
 8.5  103
18.0  103  1.8  102


Solution: Make sure that all numbers are expressed in scientific notation.







6.53  5.75  1.14


Combining the above two steps:
1. Introduction


0.749  7.49  101

6.03  106  6,030,000
Subtract the exponents, n.


Solution: Write each quantity with the same exponent, n.
[solution(솔루션)] 일반화학 7판 solution(솔루션)(사이플러스)




1.24 (a) Express 3.256  105 in nonscientific notation.

Solution: The decimal point must be moved seven places to give N, a number between 1 and 10. In this case,
Let’s write 0.0095 in such a way that n  3. We have decreased 10n by 103, so we must increase N by 103. Move the decimal point 3 places to the right.
[솔루션] 일반화학 7판 솔루션(사이플러스) 입니다..^^ 확인해보세용~

순서

(b)


(b) Division using scientific notation.
18.0  103
802.6  8.026  102

Since 0.749 is a number less than one, n is a negative integer. In this case, n  1.
1.14  102  (8)  1.14  102  8  1.14  1010
0.000000621  6.21  107

(c) Express 0.000000621 in scientific notation.
레포트 > 공학,기술계열
1.26 (a) Addition using scientific notation.
For the above number expressed in scientific notation, n  5. To convert to nonscientific notation, the decimal point must be moved 5 places to the left.
0.0095  9.5  103

Download : [솔루션] 일반화학 7판 솔루션(사이.zip( 37 )


Strategy: Lets express scientific notation as N  10n. When subtracting numbers using scientific notation, we must write each quantity with the same exponent, n. We can then subtract the N parts of the numbers, keeping the exponent, n, the same.


N  8.026


[솔루션] 일반화학 7판 솔루션(사이-4465_01_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_02_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_03_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_04_.gif [솔루션] 일반화학 7판 솔루션(사이-4465_05_.gif





N  6.21
기계, 공학, 화학, 일반, 솔루션
1.23 (a) 15,200 (b) 0.0000000778


Combining the above two steps:

설명

Solution: The decimal point must be moved two places to give N, a number between 1 and 10. In this case,



Add the N parts of the numbers, keeping the exponent, n, the same.

(c) (7.0  103)  (8.0  104)  (7.0  103)  (0.80  103)  6.2  103

[solution(솔루션)] 일반화학 7판 solution(솔루션)(사이플러스) 입니다.
(b) Express 802.6 in scientific notation.


[solution(솔루션)] 일반화학 7판 solution(솔루션)(사이플러스)
Combining the above two steps:
(b) Express 6.03  106 in nonscientific notation.


총 1장부터 22장까지의 solution(솔루션)이 있습니다. [솔루션] 일반화학 7판 솔루션(사이플러스)
1장의 해법 부분을 발췌했습니다.
REPORT 73(sv75)



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